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53116651 = 77588093
BaseRepresentation
bin1100101010011…
…1111011101011
310200221121100101
43022213323223
5102044213101
65134250231
71213325020
oct312477353
9120847311
1053116651
1127a8a365
1215956977
13b009b93
1470a9547
1549e3401
hex32a7eeb

53116651 has 4 divisors (see below), whose sum is σ = 60704752. Its totient is φ = 45528552.

The previous prime is 53116649. The next prime is 53116673. The reversal of 53116651 is 15661135.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 53116651 - 21 = 53116649 is a prime.

It is a super-2 number, since 2×531166512 = 5642757226911602, which contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (53116601) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3794040 + ... + 3794053.

It is an arithmetic number, because the mean of its divisors is an integer number (15176188).

Almost surely, 253116651 is an apocalyptic number.

53116651 is a deficient number, since it is larger than the sum of its proper divisors (7588101).

53116651 is an equidigital number, since it uses as much as digits as its factorization.

53116651 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7588100.

The product of its digits is 2700, while the sum is 28.

The square root of 53116651 is about 7288.1171093774. The cubic root of 53116651 is about 375.9039549275.

Adding to 53116651 its reverse (15661135), we get a palindrome (68777786).

The spelling of 53116651 in words is "fifty-three million, one hundred sixteen thousand, six hundred fifty-one".

Divisors: 1 7 7588093 53116651