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5310213 = 31770071
BaseRepresentation
bin10100010000011100000101
3100222210020120
4110100130011
52324411323
6305452153
763064446
oct24203405
910883216
105310213
112aa7707
121941059
13113c04c
149c32cd
156ed5e3
hex510705

5310213 has 4 divisors (see below), whose sum is σ = 7080288. Its totient is φ = 3540140.

The previous prime is 5310191. The next prime is 5310247. The reversal of 5310213 is 3120135.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 5310213 - 25 = 5310181 is a prime.

It is a D-number.

5310213 is a lucky number.

It is a junction number, because it is equal to n+sod(n) for n = 5310192 and 5310201.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5310293) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 885033 + ... + 885038.

It is an arithmetic number, because the mean of its divisors is an integer number (1770072).

Almost surely, 25310213 is an apocalyptic number.

It is an amenable number.

5310213 is a deficient number, since it is larger than the sum of its proper divisors (1770075).

5310213 is a wasteful number, since it uses less digits than its factorization.

5310213 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1770074.

The product of its (nonzero) digits is 90, while the sum is 15.

The square root of 5310213 is about 2304.3899409605. The cubic root of 5310213 is about 174.4632588498.

Adding to 5310213 its reverse (3120135), we get a palindrome (8430348).

The spelling of 5310213 in words is "five million, three hundred ten thousand, two hundred thirteen".

Divisors: 1 3 1770071 5310213