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531004343 = 1927947597
BaseRepresentation
bin11111101001100…
…111101110110111
31101000011211000112
4133221213232313
52041414114333
6124405133235
716105314422
oct3751475667
91330154015
10531004343
11252813471
121299ba21b
138601c26c
14507469b9
153193e948
hex1fa67bb7

531004343 has 4 divisors (see below), whose sum is σ = 558951960. Its totient is φ = 503056728.

The previous prime is 531004337. The next prime is 531004361. The reversal of 531004343 is 343400135.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-531004343 is a prime.

It is a super-2 number, since 2×5310043432 = 563931224569723298, which contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (531004043) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13973780 + ... + 13973817.

It is an arithmetic number, because the mean of its divisors is an integer number (139737990).

Almost surely, 2531004343 is an apocalyptic number.

531004343 is a deficient number, since it is larger than the sum of its proper divisors (27947617).

531004343 is a wasteful number, since it uses less digits than its factorization.

531004343 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 27947616.

The product of its (nonzero) digits is 2160, while the sum is 23.

The square root of 531004343 is about 23043.5314784865. The cubic root of 531004343 is about 809.7780944738.

Adding to 531004343 its reverse (343400135), we get a palindrome (874404478).

The spelling of 531004343 in words is "five hundred thirty-one million, four thousand, three hundred forty-three".

Divisors: 1 19 27947597 531004343