Base | Representation |
---|---|
bin | 1001111000100101… |
… | …00110011000000101 |
3 | 111200211001220122112 |
4 | 10330102212120011 |
5 | 41331424213122 |
6 | 2234320110405 |
7 | 245333205422 |
oct | 47422463005 |
9 | 14624056575 |
10 | 5306476037 |
11 | 2283404a95 |
12 | 1041165405 |
13 | 6674b6265 |
14 | 384a7cd49 |
15 | 210ce42e2 |
hex | 13c4a6605 |
5306476037 has 2 divisors, whose sum is σ = 5306476038. Its totient is φ = 5306476036.
The previous prime is 5306476031. The next prime is 5306476039. The reversal of 5306476037 is 7306746035.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 5264082916 + 42393121 = 72554^2 + 6511^2 .
It is a cyclic number.
It is not a de Polignac number, because 5306476037 - 26 = 5306475973 is a prime.
Together with 5306476039, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 5306475985 and 5306476003.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5306476031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2653238018 + 2653238019.
It is an arithmetic number, because the mean of its divisors is an integer number (2653238019).
Almost surely, 25306476037 is an apocalyptic number.
It is an amenable number.
5306476037 is a deficient number, since it is larger than the sum of its proper divisors (1).
5306476037 is an equidigital number, since it uses as much as digits as its factorization.
5306476037 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 317520, while the sum is 41.
The square root of 5306476037 is about 72845.5629190962. The cubic root of 5306476037 is about 1744.2232416168.
The spelling of 5306476037 in words is "five billion, three hundred six million, four hundred seventy-six thousand, thirty-seven".
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