Base | Representation |
---|---|
bin | 1001111000010010… |
… | …10100101010101011 |
3 | 111200122111100210121 |
4 | 10330021110222223 |
5 | 41330313403303 |
6 | 2234152024111 |
7 | 245303426503 |
oct | 47411245253 |
9 | 14618440717 |
10 | 5304044203 |
11 | 2281aa3a07 |
12 | 1040392037 |
13 | 666b443c3 |
14 | 384608a03 |
15 | 2109b39bd |
hex | 13c254aab |
5304044203 has 4 divisors (see below), whose sum is σ = 5304639400. Its totient is φ = 5303449008.
The previous prime is 5304044173. The next prime is 5304044209. The reversal of 5304044203 is 3024404035.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5304044203 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5304044209) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 284025 + ... + 302122.
It is an arithmetic number, because the mean of its divisors is an integer number (1326159850).
Almost surely, 25304044203 is an apocalyptic number.
5304044203 is a deficient number, since it is larger than the sum of its proper divisors (595197).
5304044203 is an equidigital number, since it uses as much as digits as its factorization.
5304044203 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 595196.
The product of its (nonzero) digits is 5760, while the sum is 25.
The square root of 5304044203 is about 72828.8692964541. The cubic root of 5304044203 is about 1743.9567553166.
Adding to 5304044203 its reverse (3024404035), we get a palindrome (8328448238).
The spelling of 5304044203 in words is "five billion, three hundred four million, forty-four thousand, two hundred three".
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