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53022035 = 5117912203
BaseRepresentation
bin1100101001000…
…0110101010011
310200202210120002
43022100311103
5102033201120
65132240215
71212452123
oct312206523
9120683502
1053022035
1127a25270
121591006b
13aca5ab1
147082c83
1549c5375
hex3290d53

53022035 has 16 divisors (see below), whose sum is σ = 70295040. Its totient is φ = 38070240.

The previous prime is 53022029. The next prime is 53022049.

53022035 is nontrivially palindromic in base 10.

It is not a de Polignac number, because 53022035 - 26 = 53021971 is a prime.

It is a super-4 number, since 4×530220354 (a number of 32 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 53021998 and 53022016.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1757 + ... + 10446.

It is an arithmetic number, because the mean of its divisors is an integer number (4393440).

Almost surely, 253022035 is an apocalyptic number.

53022035 is a gapful number since it is divisible by the number (55) formed by its first and last digit.

53022035 is a deficient number, since it is larger than the sum of its proper divisors (17273005).

53022035 is a wasteful number, since it uses less digits than its factorization.

53022035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12298.

The product of its (nonzero) digits is 900, while the sum is 20.

The square root of 53022035 is about 7281.6231020288. The cubic root of 53022035 is about 375.6806246602.

It can be divided in two parts, 5302 and 2035, that added together give a palindrome (7337).

The spelling of 53022035 in words is "fifty-three million, twenty-two thousand, thirty-five".

Divisors: 1 5 11 55 79 395 869 4345 12203 61015 134233 671165 964037 4820185 10604407 53022035