Base | Representation |
---|---|
bin | 1100101000111… |
… | …0011111010101 |
3 | 10200202022101121 |
4 | 3022032133111 |
5 | 102032344222 |
6 | 5132123541 |
7 | 1212412132 |
oct | 312163725 |
9 | 120668347 |
10 | 53012437 |
11 | 27a19035 |
12 | 159065b1 |
13 | aca160a |
14 | 707d589 |
15 | 49c25c7 |
hex | 328e7d5 |
53012437 has 2 divisors, whose sum is σ = 53012438. Its totient is φ = 53012436.
The previous prime is 53012431. The next prime is 53012441. The reversal of 53012437 is 73421035.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 39425841 + 13586596 = 6279^2 + 3686^2 .
It is a cyclic number.
It is not a de Polignac number, because 53012437 - 23 = 53012429 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53012431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26506218 + 26506219.
It is an arithmetic number, because the mean of its divisors is an integer number (26506219).
Almost surely, 253012437 is an apocalyptic number.
It is an amenable number.
53012437 is a deficient number, since it is larger than the sum of its proper divisors (1).
53012437 is an equidigital number, since it uses as much as digits as its factorization.
53012437 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2520, while the sum is 25.
The square root of 53012437 is about 7280.9640158430. The cubic root of 53012437 is about 375.6579548386.
The spelling of 53012437 in words is "fifty-three million, twelve thousand, four hundred thirty-seven".
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