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53014411 is a prime number
BaseRepresentation
bin1100101000111…
…0111110001011
310200202102002201
43022032332023
5102032430121
65132141031
71212420652
oct312167613
9120672081
1053014411
1127a1a56a
1215907777
13aca2498
147080199
1549c2e91
hex328ef8b

53014411 has 2 divisors, whose sum is σ = 53014412. Its totient is φ = 53014410.

The previous prime is 53014397. The next prime is 53014417. The reversal of 53014411 is 11441035.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 53014411 - 217 = 52883339 is a prime.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (53014417) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26507205 + 26507206.

It is an arithmetic number, because the mean of its divisors is an integer number (26507206).

Almost surely, 253014411 is an apocalyptic number.

53014411 is a deficient number, since it is larger than the sum of its proper divisors (1).

53014411 is an equidigital number, since it uses as much as digits as its factorization.

53014411 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 240, while the sum is 19.

The square root of 53014411 is about 7281.0995735534. The cubic root of 53014411 is about 375.6626175155.

Adding to 53014411 its reverse (11441035), we get a palindrome (64455446).

It can be divided in two parts, 530 and 14411, that added together give a palindrome (14941).

The spelling of 53014411 in words is "fifty-three million, fourteen thousand, four hundred eleven".