Base | Representation |
---|---|
bin | 1001110111110101… |
… | …01100111001010011 |
3 | 111200101021122000121 |
4 | 10323322230321103 |
5 | 41323323230113 |
6 | 2233533531111 |
7 | 245226024013 |
oct | 47372547123 |
9 | 14611248017 |
10 | 5300211283 |
11 | 227a916204 |
12 | 103b043a97 |
13 | 6661018c3 |
14 | 383ccbc43 |
15 | 2104a7e8d |
hex | 13beace53 |
5300211283 has 2 divisors, whose sum is σ = 5300211284. Its totient is φ = 5300211282.
The previous prime is 5300211271. The next prime is 5300211299. The reversal of 5300211283 is 3821120035.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5300211283 is a prime.
It is not a weakly prime, because it can be changed into another prime (5300211223) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2650105641 + 2650105642.
It is an arithmetic number, because the mean of its divisors is an integer number (2650105642).
Almost surely, 25300211283 is an apocalyptic number.
5300211283 is a deficient number, since it is larger than the sum of its proper divisors (1).
5300211283 is an equidigital number, since it uses as much as digits as its factorization.
5300211283 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1440, while the sum is 25.
The square root of 5300211283 is about 72802.5499759452. The cubic root of 5300211283 is about 1743.5365691800.
The spelling of 5300211283 in words is "five billion, three hundred million, two hundred eleven thousand, two hundred eighty-three".
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