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5300211121 is a prime number
BaseRepresentation
bin1001110111110101…
…01100110110110001
3111200101021121210121
410323322230312301
541323323223441
62233533530241
7245226023362
oct47372546661
914611247717
105300211121
11227a916077
12103b043981
136661017ca
14383ccbb69
152104a7dd1
hex13beacdb1

5300211121 has 2 divisors, whose sum is σ = 5300211122. Its totient is φ = 5300211120.

The previous prime is 5300211109. The next prime is 5300211151. The reversal of 5300211121 is 1211120035.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 4230201600 + 1070009521 = 65040^2 + 32711^2 .

It is a cyclic number.

It is not a de Polignac number, because 5300211121 - 215 = 5300178353 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 5300211095 and 5300211104.

It is not a weakly prime, because it can be changed into another prime (5300211151) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2650105560 + 2650105561.

It is an arithmetic number, because the mean of its divisors is an integer number (2650105561).

Almost surely, 25300211121 is an apocalyptic number.

It is an amenable number.

5300211121 is a deficient number, since it is larger than the sum of its proper divisors (1).

5300211121 is an equidigital number, since it uses as much as digits as its factorization.

5300211121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 60, while the sum is 16.

The square root of 5300211121 is about 72802.5488633468. The cubic root of 5300211121 is about 1743.5365514164.

Adding to 5300211121 its reverse (1211120035), we get a palindrome (6511331156).

The spelling of 5300211121 in words is "five billion, three hundred million, two hundred eleven thousand, one hundred twenty-one".