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52525433 is a prime number
BaseRepresentation
bin1100100001011…
…1100101111001
310122211120100102
43020113211321
5101421303213
65113445145
71205313242
oct310274571
9118746312
1052525433
1127716154
12157107b5
13ab60a4c
146d93cc9
154928158
hex3217979

52525433 has 2 divisors, whose sum is σ = 52525434. Its totient is φ = 52525432.

The previous prime is 52525411. The next prime is 52525477. The reversal of 52525433 is 33452525.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 51437584 + 1087849 = 7172^2 + 1043^2 .

It is a cyclic number.

It is not a de Polignac number, because 52525433 - 214 = 52509049 is a prime.

It is a super-2 number, since 2×525254332 = 5517842223674978, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 52525396 and 52525405.

It is not a weakly prime, because it can be changed into another prime (52525483) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26262716 + 26262717.

It is an arithmetic number, because the mean of its divisors is an integer number (26262717).

Almost surely, 252525433 is an apocalyptic number.

It is an amenable number.

52525433 is a deficient number, since it is larger than the sum of its proper divisors (1).

52525433 is an equidigital number, since it uses as much as digits as its factorization.

52525433 is an evil number, because the sum of its binary digits is even.

The product of its digits is 18000, while the sum is 29.

The square root of 52525433 is about 7247.4432043308. The cubic root of 52525433 is about 374.5040745176.

Adding to 52525433 its reverse (33452525), we get a palindrome (85977958).

The spelling of 52525433 in words is "fifty-two million, five hundred twenty-five thousand, four hundred thirty-three".