Base | Representation |
---|---|
bin | 1100100001001… |
… | …1110111000011 |
3 | 10122210210101021 |
4 | 3020103313003 |
5 | 101420311042 |
6 | 5113250311 |
7 | 1205220544 |
oct | 310236703 |
9 | 118723337 |
10 | 52510147 |
11 | 27705718 |
12 | 15703997 |
13 | ab56ac1 |
14 | 6d8c4cb |
15 | 4923867 |
hex | 3213dc3 |
52510147 has 2 divisors, whose sum is σ = 52510148. Its totient is φ = 52510146.
The previous prime is 52510103. The next prime is 52510207. The reversal of 52510147 is 74101525.
52510147 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 52510147 - 27 = 52510019 is a prime.
It is not a weakly prime, because it can be changed into another prime (52510247) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26255073 + 26255074.
It is an arithmetic number, because the mean of its divisors is an integer number (26255074).
Almost surely, 252510147 is an apocalyptic number.
52510147 is a deficient number, since it is larger than the sum of its proper divisors (1).
52510147 is an equidigital number, since it uses as much as digits as its factorization.
52510147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1400, while the sum is 25.
The square root of 52510147 is about 7246.3885487876. The cubic root of 52510147 is about 374.4677414857.
It can be divided in two parts, 5 and 2510147, that added together give a palindrome (2510152).
The spelling of 52510147 in words is "fifty-two million, five hundred ten thousand, one hundred forty-seven".
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