Base | Representation |
---|---|
bin | 1001101110110111… |
… | …11111000101100111 |
3 | 111111010212001202211 |
4 | 10313123333011213 |
5 | 41200103103341 |
6 | 2222250544251 |
7 | 243324124204 |
oct | 46733770547 |
9 | 14433761684 |
10 | 5225050471 |
11 | 224144a833 |
12 | 1019a38087 |
13 | 653677054 |
14 | 377d24cab |
15 | 208aad181 |
hex | 1376ff167 |
5225050471 has 2 divisors, whose sum is σ = 5225050472. Its totient is φ = 5225050470.
The previous prime is 5225050417. The next prime is 5225050499. The reversal of 5225050471 is 1740505225.
Together with previous prime (5225050417) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5225050471 - 221 = 5222953319 is a prime.
It is a super-3 number, since 3×52250504713 (a number of 30 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5225000471) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2612525235 + 2612525236.
It is an arithmetic number, because the mean of its divisors is an integer number (2612525236).
Almost surely, 25225050471 is an apocalyptic number.
5225050471 is a deficient number, since it is larger than the sum of its proper divisors (1).
5225050471 is an equidigital number, since it uses as much as digits as its factorization.
5225050471 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14000, while the sum is 31.
The square root of 5225050471 is about 72284.5105883688. The cubic root of 5225050471 is about 1735.2557677568.
Adding to 5225050471 its reverse (1740505225), we get a palindrome (6965555696).
The spelling of 5225050471 in words is "five billion, two hundred twenty-five million, fifty thousand, four hundred seventy-one".
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