Base | Representation |
---|---|
bin | 1100001111011… |
… | …1000000101011 |
3 | 10120121111220112 |
4 | 3003313000223 |
5 | 101120442103 |
6 | 5032244535 |
7 | 1162261136 |
oct | 303670053 |
9 | 116544815 |
10 | 51343403 |
11 | 26a89071 |
12 | 1524074b |
13 | a838a17 |
14 | 6b6721d |
15 | 4792cd8 |
hex | 30f702b |
51343403 has 8 divisors (see below), whose sum is σ = 51970800. Its totient is φ = 50719968.
The previous prime is 51343399. The next prime is 51343423. The reversal of 51343403 is 30434315.
51343403 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 51343403 - 22 = 51343399 is a prime.
It is a super-2 number, since 2×513434032 = 5272290063240818, which contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (51343423) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 31025 + ... + 32637.
It is an arithmetic number, because the mean of its divisors is an integer number (6496350).
Almost surely, 251343403 is an apocalyptic number.
51343403 is a deficient number, since it is larger than the sum of its proper divisors (627397).
51343403 is a wasteful number, since it uses less digits than its factorization.
51343403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1981.
The product of its (nonzero) digits is 2160, while the sum is 23.
The square root of 51343403 is about 7165.4311105474. The cubic root of 51343403 is about 371.6734594490.
Adding to 51343403 its reverse (30434315), we get a palindrome (81777718).
The spelling of 51343403 in words is "fifty-one million, three hundred forty-three thousand, four hundred three".
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