Base | Representation |
---|---|
bin | 1001100010011110… |
… | …00111000110010011 |
3 | 111012220002100222101 |
4 | 10301033013012103 |
5 | 40441434341430 |
6 | 2204053021231 |
7 | 240621612322 |
oct | 46117070623 |
9 | 14186070871 |
10 | 5121012115 |
11 | 219875021a |
12 | bab024817 |
13 | 637c4b3ab |
14 | 3681a20b9 |
15 | 1ee8abdca |
hex | 1313c7193 |
5121012115 has 16 divisors (see below), whose sum is σ = 6305083488. Its totient is φ = 3990744576.
The previous prime is 5121012079. The next prime is 5121012151. The reversal of 5121012115 is 5112101215.
5121012115 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is an interprime number because it is at equal distance from previous prime (5121012079) and next prime (5121012151).
It is a cyclic number.
It is not a de Polignac number, because 5121012115 - 229 = 4584141203 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 5121012092 and 5121012101.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 48267 + ... + 112123.
It is an arithmetic number, because the mean of its divisors is an integer number (394067718).
Almost surely, 25121012115 is an apocalyptic number.
5121012115 is a deficient number, since it is larger than the sum of its proper divisors (1184071373).
5121012115 is a wasteful number, since it uses less digits than its factorization.
5121012115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 64278.
The product of its (nonzero) digits is 100, while the sum is 19.
The square root of 5121012115 is about 71561.2472990794. The cubic root of 5121012115 is about 1723.6613141089.
The spelling of 5121012115 in words is "five billion, one hundred twenty-one million, twelve thousand, one hundred fifteen".
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