Base | Representation |
---|---|
bin | 10011100010000000100001 |
3 | 100122010100212 |
4 | 103202000201 |
5 | 2302320113 |
6 | 301423505 |
7 | 61343132 |
oct | 23420041 |
9 | 10563325 |
10 | 5120033 |
11 | 2987836 |
12 | 186ab95 |
13 | 10a3609 |
14 | 973c89 |
15 | 6b20a8 |
hex | 4e2021 |
5120033 has 2 divisors, whose sum is σ = 5120034. Its totient is φ = 5120032.
The previous prime is 5120029. The next prime is 5120047. The reversal of 5120033 is 3300215.
It is an a-pointer prime, because the next prime (5120047) can be obtained adding 5120033 to its sum of digits (14).
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2845969 + 2274064 = 1687^2 + 1508^2 .
It is a cyclic number.
It is not a de Polignac number, because 5120033 - 22 = 5120029 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is not a weakly prime, because it can be changed into another prime (5120333) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (7) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2560016 + 2560017.
It is an arithmetic number, because the mean of its divisors is an integer number (2560017).
Almost surely, 25120033 is an apocalyptic number.
It is an amenable number.
5120033 is a deficient number, since it is larger than the sum of its proper divisors (1).
5120033 is an equidigital number, since it uses as much as digits as its factorization.
5120033 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 90, while the sum is 14.
The square root of 5120033 is about 2262.7489918239. The cubic root of 5120033 is about 172.3551454952.
Adding to 5120033 its reverse (3300215), we get a palindrome (8420248).
The spelling of 5120033 in words is "five million, one hundred twenty thousand, thirty-three".
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