51125117 has 2 divisors, whose sum is σ = 51125118. Its totient is φ = 51125116.

The previous prime is 51125077. The next prime is 51125119. The reversal of 51125117 is 71152115.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 50395801 + 729316 = 7099^2 + 854^2 .

It is a cyclic number.

It is not a de Polignac number, because 51125117 - 2¹⁰ = 51124093 is a prime.

It is a super-2 number, since 2×51125117² = 5227555176527378, which contains 22 as substring.

Together with 51125119, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 51125092 and 51125101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (51125119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25562558 + 25562559.

It is an arithmetic number, because the mean of its divisors is an integer number (25562559).

Almost surely, 2^51125117 is an apocalyptic number.

It is an amenable number.

51125117 is a deficient number, since it is larger than the sum of its proper divisors (1).

51125117 is an equidigital number, since it uses as much as digits as its factorization.

51125117 is an evil number, because the sum of its binary digits is even.

The product of its digits is 350, while the sum is 23.

The square root of 51125117 is about 7150.1830046510. The cubic root of 51125117 is about 371.1459891450.

The spelling of 51125117 in words is "fifty-one million, one hundred twenty-five thousand, one hundred seventeen".