51114433 has 2 divisors, whose sum is σ = 51114434. Its totient is φ = 51114432.

The previous prime is 51114431. The next prime is 51114439. The reversal of 51114433 is 33441115.

51114433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 36276529 + 14837904 = 6023^2 + 3852^2 .

It is a cyclic number.

It is not a de Polignac number, because 51114433 - 2¹ = 51114431 is a prime.

It is a super-2 number, since 2×51114433² = 5225370521822978, which contains 22 as substring.

Together with 51114431, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (51114431) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25557216 + 25557217.

It is an arithmetic number, because the mean of its divisors is an integer number (25557217).

Almost surely, 2^51114433 is an apocalyptic number.

It is an amenable number.

51114433 is a deficient number, since it is larger than the sum of its proper divisors (1).

51114433 is an equidigital number, since it uses as much as digits as its factorization.

51114433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 720, while the sum is 22.

The square root of 51114433 is about 7149.4358518697. The cubic root of 51114433 is about 371.1201336214.

Adding to 51114433 its reverse (33441115), we get a palindrome (84555548).

The spelling of 51114433 in words is "fifty-one million, one hundred fourteen thousand, four hundred thirty-three".