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51023081 is a prime number
BaseRepresentation
bin1100001010100…
…0110011101001
310120000020111202
43002220303221
5101030214311
65021333545
71156455224
oct302506351
9116006452
1051023081
112688a43a
12151072b5
13a755c95
146ac25bb
15472ce3b
hex30a8ce9

51023081 has 2 divisors, whose sum is σ = 51023082. Its totient is φ = 51023080.

The previous prime is 51023053. The next prime is 51023083. The reversal of 51023081 is 18032015.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 48163600 + 2859481 = 6940^2 + 1691^2 .

It is a cyclic number.

It is not a de Polignac number, because 51023081 - 210 = 51022057 is a prime.

It is a super-2 number, since 2×510230812 = 5206709589465122, which contains 22 as substring.

Together with 51023083, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (51023083) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25511540 + 25511541.

It is an arithmetic number, because the mean of its divisors is an integer number (25511541).

Almost surely, 251023081 is an apocalyptic number.

It is an amenable number.

51023081 is a deficient number, since it is larger than the sum of its proper divisors (1).

51023081 is an equidigital number, since it uses as much as digits as its factorization.

51023081 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 240, while the sum is 20.

The square root of 51023081 is about 7143.0442389782. The cubic root of 51023081 is about 370.8989124549.

Adding to 51023081 its reverse (18032015), we get a palindrome (69055096).

The spelling of 51023081 in words is "fifty-one million, twenty-three thousand, eighty-one".