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509913143 is a prime number
BaseRepresentation
bin11110011001001…
…010100000110111
31022112111021022222
4132121022200313
52021014210033
6122333112555
715431122145
oct3631124067
91275437288
10509913143
11241918323
1212292875b
138184626c
144ba16595
152eb75598
hex1e64a837

509913143 has 2 divisors, whose sum is σ = 509913144. Its totient is φ = 509913142.

The previous prime is 509913137. The next prime is 509913161. The reversal of 509913143 is 341319905.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-509913143 is a prime.

It is a super-2 number, since 2×5099131432 = 520022826808276898, which contains 22 as substring.

It is a Sophie Germain prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (509913193) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 254956571 + 254956572.

It is an arithmetic number, because the mean of its divisors is an integer number (254956572).

Almost surely, 2509913143 is an apocalyptic number.

509913143 is a deficient number, since it is larger than the sum of its proper divisors (1).

509913143 is an equidigital number, since it uses as much as digits as its factorization.

509913143 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 14580, while the sum is 35.

The square root of 509913143 is about 22581.2564530852. The cubic root of 509913143 is about 798.9116152573.

The spelling of 509913143 in words is "five hundred nine million, nine hundred thirteen thousand, one hundred forty-three".