Base | Representation |
---|---|
bin | 11110001000011… |
… | …001001111111101 |
3 | 1022020012221000211 |
4 | 132020121033331 |
5 | 2013403021203 |
6 | 122054552421 |
7 | 15345552436 |
oct | 3610311775 |
9 | 1266187024 |
10 | 505517053 |
11 | 23a395498 |
12 | 121368711 |
13 | 80967322 |
14 | 4b1d048d |
15 | 2e5a7c6d |
hex | 1e2193fd |
505517053 has 2 divisors, whose sum is σ = 505517054. Its totient is φ = 505517052.
The previous prime is 505517029. The next prime is 505517057. The reversal of 505517053 is 350715505.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 505440324 + 76729 = 22482^2 + 277^2 .
It is a cyclic number.
It is not a de Polignac number, because 505517053 - 217 = 505385981 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (505517057) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 252758526 + 252758527.
It is an arithmetic number, because the mean of its divisors is an integer number (252758527).
Almost surely, 2505517053 is an apocalyptic number.
It is an amenable number.
505517053 is a deficient number, since it is larger than the sum of its proper divisors (1).
505517053 is an equidigital number, since it uses as much as digits as its factorization.
505517053 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 13125, while the sum is 31.
The square root of 505517053 is about 22483.7063892944. The cubic root of 505517053 is about 796.6091127655.
The spelling of 505517053 in words is "five hundred five million, five hundred seventeen thousand, fifty-three".
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