Base | Representation |
---|---|
bin | 1010101000111100… |
… | …01110011110010111 |
3 | 112202002110122210212 |
4 | 11110132032132113 |
5 | 43144304131142 |
6 | 2342451440035 |
7 | 261360463253 |
oct | 52436163627 |
9 | 15662418725 |
10 | 5712177047 |
11 | 2471414185 |
12 | 1134bb601b |
13 | 700572725 |
14 | 3c28c9263 |
15 | 236731d82 |
hex | 15478e797 |
5712177047 has 2 divisors, whose sum is σ = 5712177048. Its totient is φ = 5712177046.
The previous prime is 5712177017. The next prime is 5712177049. The reversal of 5712177047 is 7407712175.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5712177047 is a prime.
Together with 5712177049, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 5712176995 and 5712177013.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5712177049) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2856088523 + 2856088524.
It is an arithmetic number, because the mean of its divisors is an integer number (2856088524).
Almost surely, 25712177047 is an apocalyptic number.
5712177047 is a deficient number, since it is larger than the sum of its proper divisors (1).
5712177047 is an equidigital number, since it uses as much as digits as its factorization.
5712177047 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 96040, while the sum is 41.
The square root of 5712177047 is about 75578.9457918010. The cubic root of 5712177047 is about 1787.5871328709.
The spelling of 5712177047 in words is "five billion, seven hundred twelve million, one hundred seventy-seven thousand, forty-seven".
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