Base | Representation |
---|---|
bin | 1101100111101… |
… | …0100111010111 |
3 | 10222111021020011 |
4 | 3121322213113 |
5 | 104111002320 |
6 | 5400221051 |
7 | 1262362111 |
oct | 331724727 |
9 | 128437204 |
10 | 57125335 |
11 | 2a278123 |
12 | 1716a787 |
13 | bab1697 |
14 | 78303b1 |
15 | 503605a |
hex | 367a9d7 |
57125335 has 4 divisors (see below), whose sum is σ = 68550408. Its totient is φ = 45700264.
The previous prime is 57125329. The next prime is 57125357. The reversal of 57125335 is 53352175.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 57125335 - 25 = 57125303 is a prime.
It is a Smith number, since the sum of its digits (31) coincides with the sum of the digits of its prime factors. Since it is squarefree, it is also a hoax number.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 57125297 and 57125306.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5712529 + ... + 5712538.
It is an arithmetic number, because the mean of its divisors is an integer number (17137602).
Almost surely, 257125335 is an apocalyptic number.
57125335 is a deficient number, since it is larger than the sum of its proper divisors (11425073).
57125335 is a wasteful number, since it uses less digits than its factorization.
57125335 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 11425072.
The product of its digits is 15750, while the sum is 31.
The square root of 57125335 is about 7558.1303905133. The cubic root of 57125335 is about 385.1319837588.
The spelling of 57125335 in words is "fifty-seven million, one hundred twenty-five thousand, three hundred thirty-five".
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