Base | Representation |
---|---|
bin | 1010001111101010… |
… | …00000010000101011 |
3 | 112012022022012102121 |
4 | 11013311000100223 |
5 | 42231002404311 |
6 | 2305433012111 |
7 | 253203414445 |
oct | 50765002053 |
9 | 15168265377 |
10 | 5500044331 |
11 | 23726a4791 |
12 | 1095b54037 |
13 | 69862ac02 |
14 | 3a2669495 |
15 | 222cccb71 |
hex | 147d4042b |
5500044331 has 4 divisors (see below), whose sum is σ = 5504969392. Its totient is φ = 5495119272.
The previous prime is 5500044317. The next prime is 5500044337. The reversal of 5500044331 is 1334400055.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5500044331 - 215 = 5500011563 is a prime.
It is a super-2 number, since 2×55000443312 = 60500975285930475122, which contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 5500044296 and 5500044305.
It is not an unprimeable number, because it can be changed into a prime (5500044337) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2460855 + ... + 2463088.
It is an arithmetic number, because the mean of its divisors is an integer number (1376242348).
Almost surely, 25500044331 is an apocalyptic number.
5500044331 is a deficient number, since it is larger than the sum of its proper divisors (4925061).
5500044331 is a wasteful number, since it uses less digits than its factorization.
5500044331 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4925060.
The product of its (nonzero) digits is 3600, while the sum is 25.
The square root of 5500044331 is about 74162.2837498954. The cubic root of 5500044331 is about 1765.1789101919.
Adding to 5500044331 its reverse (1334400055), we get a palindrome (6834444386).
The spelling of 5500044331 in words is "five billion, five hundred million, forty-four thousand, three hundred thirty-one".
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