Base | Representation |
---|---|
bin | 1010001000011111… |
… | …01101110001001001 |
3 | 112001010012110111201 |
4 | 11010033231301021 |
5 | 42120111000414 |
6 | 2255444424201 |
7 | 251543464261 |
oct | 50417556111 |
9 | 15033173451 |
10 | 5439937609 |
11 | 2341780707 |
12 | 10799a8061 |
13 | 6890444c2 |
14 | 3986a07a1 |
15 | 21c8a8574 |
hex | 1443edc49 |
5439937609 has 2 divisors, whose sum is σ = 5439937610. Its totient is φ = 5439937608.
The previous prime is 5439937603. The next prime is 5439937631. The reversal of 5439937609 is 9067399345.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 4844577609 + 595360000 = 69603^2 + 24400^2 .
It is a cyclic number.
It is not a de Polignac number, because 5439937609 - 211 = 5439935561 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 5439937609.
It is not a weakly prime, because it can be changed into another prime (5439937603) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2719968804 + 2719968805.
It is an arithmetic number, because the mean of its divisors is an integer number (2719968805).
Almost surely, 25439937609 is an apocalyptic number.
It is an amenable number.
5439937609 is a deficient number, since it is larger than the sum of its proper divisors (1).
5439937609 is an equidigital number, since it uses as much as digits as its factorization.
5439937609 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5511240, while the sum is 55.
The square root of 5439937609 is about 73755.9327037493. The cubic root of 5439937609 is about 1758.7251452444.
The spelling of 5439937609 in words is "five billion, four hundred thirty-nine million, nine hundred thirty-seven thousand, six hundred nine".
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