Base | Representation |
---|---|
bin | 1100111101000… |
… | …0011010011011 |
3 | 10210020022011120 |
4 | 3033100122123 |
5 | 102402043120 |
6 | 5220300323 |
7 | 1226543343 |
oct | 317203233 |
9 | 123208146 |
10 | 54331035 |
11 | 28739790 |
12 | 162416a3 |
13 | b343855 |
14 | 7303d23 |
15 | 4b83140 |
hex | 33d069b |
54331035 has 32 divisors (see below), whose sum is σ = 96456960. Its totient is φ = 25891200.
The previous prime is 54331033. The next prime is 54331073. The reversal of 54331035 is 53013345.
It is a happy number.
It is not a de Polignac number, because 54331035 - 21 = 54331033 is a prime.
It is a super-2 number, since 2×543310352 = 5903722728342450, which contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 54330996 and 54331014.
It is not an unprimeable number, because it can be changed into a prime (54331033) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 6945 + ... + 12525.
It is an arithmetic number, because the mean of its divisors is an integer number (3014280).
Almost surely, 254331035 is an apocalyptic number.
54331035 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
54331035 is a deficient number, since it is larger than the sum of its proper divisors (42125925).
54331035 is a wasteful number, since it uses less digits than its factorization.
54331035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5659.
The product of its (nonzero) digits is 2700, while the sum is 24.
The square root of 54331035 is about 7370.9588928443. The cubic root of 54331035 is about 378.7471086492.
It can be divided in two parts, 543310 and 35, that added together give a palindrome (543345).
The spelling of 54331035 in words is "fifty-four million, three hundred thirty-one thousand, thirty-five".
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