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54142133 is a prime number
BaseRepresentation
bin1100111010001…
…0010010110101
310202212201001012
43032202102311
5102330022013
65212242005
71225125533
oct316422265
9122781035
1054142133
112861a871
1216170305
13b2a8886
147295153
154b471a8
hex33a24b5

54142133 has 2 divisors, whose sum is σ = 54142134. Its totient is φ = 54142132.

The previous prime is 54142103. The next prime is 54142141. The reversal of 54142133 is 33124145.

54142133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 53904964 + 237169 = 7342^2 + 487^2 .

It is a cyclic number.

It is not a de Polignac number, because 54142133 - 28 = 54141877 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 54142099 and 54142108.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (54142103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27071066 + 27071067.

It is an arithmetic number, because the mean of its divisors is an integer number (27071067).

Almost surely, 254142133 is an apocalyptic number.

It is an amenable number.

54142133 is a deficient number, since it is larger than the sum of its proper divisors (1).

54142133 is an equidigital number, since it uses as much as digits as its factorization.

54142133 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1440, while the sum is 23.

The square root of 54142133 is about 7358.1337987291. The cubic root of 54142133 is about 378.3076473254.

Adding to 54142133 its reverse (33124145), we get a palindrome (87266278).

The spelling of 54142133 in words is "fifty-four million, one hundred forty-two thousand, one hundred thirty-three".