Base | Representation |
---|---|
bin | 1100111000101… |
… | …0001000001111 |
3 | 10202200200021012 |
4 | 3032022020033 |
5 | 102313340101 |
6 | 5210155435 |
7 | 1224234131 |
oct | 316121017 |
9 | 122620235 |
10 | 54043151 |
11 | 28562468 |
12 | 16122b7b |
13 | b2727c6 |
14 | 726b051 |
15 | 4b27bbb |
hex | 338a20f |
54043151 has 2 divisors, whose sum is σ = 54043152. Its totient is φ = 54043150.
The previous prime is 54043127. The next prime is 54043177. The reversal of 54043151 is 15134045.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-54043151 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (54043751) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27021575 + 27021576.
It is an arithmetic number, because the mean of its divisors is an integer number (27021576).
Almost surely, 254043151 is an apocalyptic number.
54043151 is a deficient number, since it is larger than the sum of its proper divisors (1).
54043151 is an equidigital number, since it uses as much as digits as its factorization.
54043151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1200, while the sum is 23.
The square root of 54043151 is about 7351.4046957027. The cubic root of 54043151 is about 378.0769675208.
Adding to 54043151 its reverse (15134045), we get a palindrome (69177196).
The spelling of 54043151 in words is "fifty-four million, forty-three thousand, one hundred fifty-one".
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