Base | Representation |
---|---|
bin | 1100111000001… |
… | …0010110100111 |
3 | 10202122001120122 |
4 | 3032002112213 |
5 | 102311330203 |
6 | 5205352155 |
7 | 1224042233 |
oct | 316022647 |
9 | 122561518 |
10 | 54011303 |
11 | 28540545 |
12 | 1610865b |
13 | b261168 |
14 | 725d5c3 |
15 | 4b1d538 |
hex | 33825a7 |
54011303 has 2 divisors, whose sum is σ = 54011304. Its totient is φ = 54011302.
The previous prime is 54011299. The next prime is 54011317. The reversal of 54011303 is 30311045.
54011303 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 54011303 - 22 = 54011299 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (54011323) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27005651 + 27005652.
It is an arithmetic number, because the mean of its divisors is an integer number (27005652).
Almost surely, 254011303 is an apocalyptic number.
54011303 is a deficient number, since it is larger than the sum of its proper divisors (1).
54011303 is an equidigital number, since it uses as much as digits as its factorization.
54011303 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 180, while the sum is 17.
The square root of 54011303 is about 7349.2382598471. The cubic root of 54011303 is about 378.0026851428.
Adding to 54011303 its reverse (30311045), we get a palindrome (84322348).
The spelling of 54011303 in words is "fifty-four million, eleven thousand, three hundred three".
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