43420031 has 2 divisors, whose sum is σ = 43420032. Its totient is φ = 43420030.

The previous prime is 43420007. The next prime is 43420033. The reversal of 43420031 is 13002434.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 43420031 - 2²² = 39225727 is a prime.

It is a super-2 number, since 2×43420031² = 3770598184081922, which contains 22 as substring.

Together with 43420033, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 43419991 and 43420009.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (43420033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21710015 + 21710016.

It is an arithmetic number, because the mean of its divisors is an integer number (21710016).

Almost surely, 2^43420031 is an apocalyptic number.

43420031 is a deficient number, since it is larger than the sum of its proper divisors (1).

43420031 is an equidigital number, since it uses as much as digits as its factorization.

43420031 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 288, while the sum is 17.

The square root of 43420031 is about 6589.3877560817. The cubic root of 43420031 is about 351.4768372200.

Adding to 43420031 its reverse (13002434), we get a palindrome (56422465).

The spelling of 43420031 in words is "forty-three million, four hundred twenty thousand, thirty-one".