434010131 has 2 divisors, whose sum is σ = 434010132. Its totient is φ = 434010130.

The previous prime is 434010097. The next prime is 434010139. The reversal of 434010131 is 131010434.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 434010131 - 2⁶ = 434010067 is a prime.

It is a super-2 number, since 2×434010131² = 376729587621274322, which contains 22 as substring.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (434010139) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 217005065 + 217005066.

It is an arithmetic number, because the mean of its divisors is an integer number (217005066).

Almost surely, 2^434010131 is an apocalyptic number.

434010131 is a deficient number, since it is larger than the sum of its proper divisors (1).

434010131 is an equidigital number, since it uses as much as digits as its factorization.

434010131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 17.

The square root of 434010131 is about 20832.9098063617. The cubic root of 434010131 is about 757.1233189842.

Adding to 434010131 its reverse (131010434), we get a palindrome (565020565).

The spelling of 434010131 in words is "four hundred thirty-four million, ten thousand, one hundred thirty-one".