4331000113 has 4 divisors (see below), whose sum is σ = 4724727408. Its totient is φ = 3937272820.

The previous prime is 4331000077. The next prime is 4331000117. The reversal of 4331000113 is 3110001334.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 4331000113 - 2¹⁷ = 4330869041 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (4331000117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 196863631 + ... + 196863652.

It is an arithmetic number, because the mean of its divisors is an integer number (1181181852).

Almost surely, 2^4331000113 is an apocalyptic number.

It is an amenable number.

4331000113 is a deficient number, since it is larger than the sum of its proper divisors (393727295).

4331000113 is a wasteful number, since it uses less digits than its factorization.

4331000113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 393727294.

The product of its (nonzero) digits is 108, while the sum is 16.

The square root of 4331000113 is about 65810.3343936194. The cubic root of 4331000113 is about 1630.0317548106.

Adding to 4331000113 its reverse (3110001334), we get a palindrome (7441001447).

The spelling of 4331000113 in words is "four billion, three hundred thirty-one million, one hundred thirteen", and thus it is an aban number.