Base | Representation |
---|---|
bin | 1111101100101100… |
… | …1001100110011011 |
3 | 101212200101120220210 |
4 | 3323023021212123 |
5 | 32112241112443 |
6 | 1534052422203 |
7 | 206266305210 |
oct | 37313114633 |
9 | 11780346823 |
10 | 4214004123 |
11 | 187277173a |
12 | 997317963 |
13 | 52206cc84 |
14 | 2bd93db07 |
15 | 199e48c33 |
hex | fb2c999b |
4214004123 has 16 divisors (see below), whose sum is σ = 6642766080. Its totient is φ = 2324967456.
The previous prime is 4214004103. The next prime is 4214004139. The reversal of 4214004123 is 3214004124.
4214004123 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 4214004123 - 212 = 4214000027 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (21).
It is a self number, because there is not a number n which added to its sum of digits gives 4214004123.
It is not an unprimeable number, because it can be changed into a prime (4214004103) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3459165 + ... + 3460382.
It is an arithmetic number, because the mean of its divisors is an integer number (415172880).
Almost surely, 24214004123 is an apocalyptic number.
4214004123 is a deficient number, since it is larger than the sum of its proper divisors (2428761957).
4214004123 is a wasteful number, since it uses less digits than its factorization.
4214004123 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6919586.
The product of its (nonzero) digits is 768, while the sum is 21.
The square root of 4214004123 is about 64915.3612252139. The cubic root of 4214004123 is about 1615.2198830930.
Adding to 4214004123 its reverse (3214004124), we get a palindrome (7428008247).
Subtracting from 4214004123 its reverse (3214004124), we obtain a palindrome (999999999).
The spelling of 4214004123 in words is "four billion, two hundred fourteen million, four thousand, one hundred twenty-three".
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