4213540433 has 2 divisors, whose sum is σ = 4213540434. Its totient is φ = 4213540432.

The previous prime is 4213540351. The next prime is 4213540447. The reversal of 4213540433 is 3340453124.

4213540433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3803558929 + 409981504 = 61673^2 + 20248^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-4213540433 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 4213540396 and 4213540405.

It is not a weakly prime, because it can be changed into another prime (4213540033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2106770216 + 2106770217.

It is an arithmetic number, because the mean of its divisors is an integer number (2106770217).

Almost surely, 2^4213540433 is an apocalyptic number.

It is an amenable number.

4213540433 is a deficient number, since it is larger than the sum of its proper divisors (1).

4213540433 is an equidigital number, since it uses as much as digits as its factorization.

4213540433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 17280, while the sum is 29.

The square root of 4213540433 is about 64911.7896302359. The cubic root of 4213540433 is about 1615.1606370839.

Adding to 4213540433 its reverse (3340453124), we get a palindrome (7553993557).

The spelling of 4213540433 in words is "four billion, two hundred thirteen million, five hundred forty thousand, four hundred thirty-three".