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4200103 is a prime number
BaseRepresentation
bin10000000001011010100111
321220101110101
4100001122213
52033400403
6230004531
750462125
oct20013247
97811411
104200103
112409666
1214a6747
13b4098b
147b4915
1557e71d
hex4016a7

4200103 has 2 divisors, whose sum is σ = 4200104. Its totient is φ = 4200102.

The previous prime is 4200073. The next prime is 4200109. The reversal of 4200103 is 3010024.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-4200103 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 4200103.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4200109) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2100051 + 2100052.

It is an arithmetic number, because the mean of its divisors is an integer number (2100052).

Almost surely, 24200103 is an apocalyptic number.

4200103 is a deficient number, since it is larger than the sum of its proper divisors (1).

4200103 is an equidigital number, since it uses as much as digits as its factorization.

4200103 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24, while the sum is 10.

The square root of 4200103 is about 2049.4152824647. The cubic root of 4200103 is about 161.3441835056.

Adding to 4200103 its reverse (3010024), we get a palindrome (7210127).

The spelling of 4200103 in words is "four million, two hundred thousand, one hundred three".