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412014331 is a prime number
BaseRepresentation
bin11000100011101…
…101011011111011
31001201021111102001
4120203231123323
51320433424311
6104514521431
713132030651
oct3043553373
91051244361
10412014331
111a1631513
12b5b96277
1367489c81
143ca10dd1
15262884c1
hex188ed6fb

412014331 has 2 divisors, whose sum is σ = 412014332. Its totient is φ = 412014330.

The previous prime is 412014319. The next prime is 412014359. The reversal of 412014331 is 133410214.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 412014331 - 25 = 412014299 is a prime.

It is a super-2 number, since 2×4120143312 = 339511617898755122, which contains 22 as substring.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 412014299 and 412014308.

It is not a weakly prime, because it can be changed into another prime (412014301) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 206007165 + 206007166.

It is an arithmetic number, because the mean of its divisors is an integer number (206007166).

Almost surely, 2412014331 is an apocalyptic number.

412014331 is a deficient number, since it is larger than the sum of its proper divisors (1).

412014331 is an equidigital number, since it uses as much as digits as its factorization.

412014331 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 288, while the sum is 19.

The square root of 412014331 is about 20298.1361459618. The cubic root of 412014331 is about 744.1105135822.

Adding to 412014331 its reverse (133410214), we get a palindrome (545424545).

The spelling of 412014331 in words is "four hundred twelve million, fourteen thousand, three hundred thirty-one".