Base | Representation |
---|---|
bin | 1111010110010100… |
… | …0011111101000001 |
3 | 101122010202110112212 |
4 | 3311211003331001 |
5 | 31414223232231 |
6 | 1520500431505 |
7 | 204046361564 |
oct | 36545037501 |
9 | 11563673485 |
10 | 4120133441 |
11 | 1824787266 |
12 | 96b9a8595 |
13 | 5087942a8 |
14 | 2b12a64db |
15 | 191aa542b |
hex | f5943f41 |
4120133441 has 2 divisors, whose sum is σ = 4120133442. Its totient is φ = 4120133440.
The previous prime is 4120133429. The next prime is 4120133449. The reversal of 4120133441 is 1443310214.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3273556225 + 846577216 = 57215^2 + 29096^2 .
It is a cyclic number.
It is not a de Polignac number, because 4120133441 - 230 = 3046391617 is a prime.
It is not a weakly prime, because it can be changed into another prime (4120133449) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2060066720 + 2060066721.
It is an arithmetic number, because the mean of its divisors is an integer number (2060066721).
Almost surely, 24120133441 is an apocalyptic number.
It is an amenable number.
4120133441 is a deficient number, since it is larger than the sum of its proper divisors (1).
4120133441 is an equidigital number, since it uses as much as digits as its factorization.
4120133441 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1152, while the sum is 23.
The square root of 4120133441 is about 64188.2656020553. The cubic root of 4120133441 is about 1603.1362236768.
Adding to 4120133441 its reverse (1443310214), we get a palindrome (5563443655).
The spelling of 4120133441 in words is "four billion, one hundred twenty million, one hundred thirty-three thousand, four hundred forty-one".
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