Base | Representation |
---|---|
bin | 1111010100011011… |
… | …1001000011000011 |
3 | 101121120212122110022 |
4 | 3311012321003003 |
5 | 31410212140301 |
6 | 1520015124055 |
7 | 203622221366 |
oct | 36506710303 |
9 | 11546778408 |
10 | 4112224451 |
11 | 1820275105 |
12 | 96921362b |
13 | 506c5540a |
14 | 2b02080dd |
15 | 191041d1b |
hex | f51b90c3 |
4112224451 has 2 divisors, whose sum is σ = 4112224452. Its totient is φ = 4112224450.
The previous prime is 4112224423. The next prime is 4112224481. The reversal of 4112224451 is 1544222114.
4112224451 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4112224451 - 26 = 4112224387 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 4112224451.
It is not a weakly prime, because it can be changed into another prime (4112224481) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2056112225 + 2056112226.
It is an arithmetic number, because the mean of its divisors is an integer number (2056112226).
Almost surely, 24112224451 is an apocalyptic number.
4112224451 is a deficient number, since it is larger than the sum of its proper divisors (1).
4112224451 is an equidigital number, since it uses as much as digits as its factorization.
4112224451 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2560, while the sum is 26.
The square root of 4112224451 is about 64126.6282522323. The cubic root of 4112224451 is about 1602.1097755307.
Adding to 4112224451 its reverse (1544222114), we get a palindrome (5656446565).
The spelling of 4112224451 in words is "four billion, one hundred twelve million, two hundred twenty-four thousand, four hundred fifty-one".
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