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4112540281 is a prime number
BaseRepresentation
bin1111010100100000…
…0110001001111001
3101121121110200200201
43311020012021321
531410302242111
61520030002201
7203625005233
oct36510061171
911547420621
104112540281
111820470423
12969346361
135070360b5
142b028b253
151910a56c1
hexf5206279

4112540281 has 2 divisors, whose sum is σ = 4112540282. Its totient is φ = 4112540280.

The previous prime is 4112540251. The next prime is 4112540293. The reversal of 4112540281 is 1820452114.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3250824256 + 861716025 = 57016^2 + 29355^2 .

It is a cyclic number.

It is not a de Polignac number, because 4112540281 - 27 = 4112540153 is a prime.

It is a super-2 number, since 2×41125402812 = 33825975125695117922, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (4112540251) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2056270140 + 2056270141.

It is an arithmetic number, because the mean of its divisors is an integer number (2056270141).

Almost surely, 24112540281 is an apocalyptic number.

It is an amenable number.

4112540281 is a deficient number, since it is larger than the sum of its proper divisors (1).

4112540281 is an equidigital number, since it uses as much as digits as its factorization.

4112540281 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2560, while the sum is 28.

The square root of 4112540281 is about 64129.0907545086. The cubic root of 4112540281 is about 1602.1507899405.

Adding to 4112540281 its reverse (1820452114), we get a palindrome (5932992395).

It can be divided in two parts, 41125 and 40281, that added together give a triangular number (81406 = T403).

The spelling of 4112540281 in words is "four billion, one hundred twelve million, five hundred forty thousand, two hundred eighty-one".