Base | Representation |
---|---|
bin | 1111010100001101… |
… | …1011000011000101 |
3 | 101121112011110010011 |
4 | 3311003123003011 |
5 | 31404444041031 |
6 | 1515543430221 |
7 | 203611413343 |
oct | 36503330305 |
9 | 11545143104 |
10 | 4111315141 |
11 | 181a803a0a |
12 | 968a55371 |
13 | 5069c756b |
14 | 2b004c993 |
15 | 190e126b1 |
hex | f50db0c5 |
4111315141 has 2 divisors, whose sum is σ = 4111315142. Its totient is φ = 4111315140.
The previous prime is 4111315121. The next prime is 4111315189. The reversal of 4111315141 is 1415131114.
4111315141 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2457184900 + 1654130241 = 49570^2 + 40671^2 .
It is a cyclic number.
It is not a de Polignac number, because 4111315141 - 213 = 4111306949 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4111315121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2055657570 + 2055657571.
It is an arithmetic number, because the mean of its divisors is an integer number (2055657571).
Almost surely, 24111315141 is an apocalyptic number.
It is an amenable number.
4111315141 is a deficient number, since it is larger than the sum of its proper divisors (1).
4111315141 is an equidigital number, since it uses as much as digits as its factorization.
4111315141 is an evil number, because the sum of its binary digits is even.
The product of its digits is 240, while the sum is 22.
The square root of 4111315141 is about 64119.5379038246. The cubic root of 4111315141 is about 1601.9916787156.
Adding to 4111315141 its reverse (1415131114), we get a palindrome (5526446255).
The spelling of 4111315141 in words is "four billion, one hundred eleven million, three hundred fifteen thousand, one hundred forty-one".
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