Base | Representation |
---|---|
bin | 1111010011111011… |
… | …1001101101110010 |
3 | 101121102221020110022 |
4 | 3310332321231302 |
5 | 31404143130114 |
6 | 1515502203442 |
7 | 203565346253 |
oct | 36476715562 |
9 | 11542836408 |
10 | 4110130034 |
11 | 181a07458a |
12 | 968583582 |
13 | 5066a100a |
14 | 2adc20b2a |
15 | 190c7b48e |
hex | f4fb9b72 |
4110130034 has 16 divisors (see below), whose sum is σ = 6318738720. Its totient is φ = 2003934240.
The previous prime is 4110129983. The next prime is 4110130091. The reversal of 4110130034 is 4300310114.
It is a junction number, because it is equal to n+sod(n) for n = 4110129994 and 4110130021.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 167177 + ... + 190179.
It is an arithmetic number, because the mean of its divisors is an integer number (394921170).
Almost surely, 24110130034 is an apocalyptic number.
4110130034 is a deficient number, since it is larger than the sum of its proper divisors (2208608686).
4110130034 is a wasteful number, since it uses less digits than its factorization.
4110130034 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 25225.
The product of its (nonzero) digits is 144, while the sum is 17.
The square root of 4110130034 is about 64110.2958501987. The cubic root of 4110130034 is about 1601.8377365716.
Adding to 4110130034 its reverse (4300310114), we get a palindrome (8410440148).
The spelling of 4110130034 in words is "four billion, one hundred ten million, one hundred thirty thousand, thirty-four".
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