Base | Representation |
---|---|
bin | 1001110010010… |
… | …0100000101101 |
3 | 2212020020210122 |
4 | 2130210200231 |
5 | 41001402023 |
6 | 4023414325 |
7 | 1005603563 |
oct | 234444055 |
9 | 85206718 |
10 | 41044013 |
11 | 21193a7a |
12 | 118b43a5 |
13 | 8670aca |
14 | 5645a33 |
15 | 390b2c8 |
hex | 272482d |
41044013 has 4 divisors (see below), whose sum is σ = 41061948. Its totient is φ = 41026080.
The previous prime is 41044007. The next prime is 41044021. The reversal of 41044013 is 31044014.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 25020004 + 16024009 = 5002^2 + 4003^2 .
It is a cyclic number.
It is not a de Polignac number, because 41044013 - 24 = 41043997 is a prime.
It is a super-2 number, since 2×410440132 = 3369222006288338, which contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 41043982 and 41044000.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (41034013) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (11) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4928 + ... + 10313.
It is an arithmetic number, because the mean of its divisors is an integer number (10265487).
Almost surely, 241044013 is an apocalyptic number.
It is an amenable number.
41044013 is a deficient number, since it is larger than the sum of its proper divisors (17935).
41044013 is a wasteful number, since it uses less digits than its factorization.
41044013 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 17934.
The product of its (nonzero) digits is 192, while the sum is 17.
The square root of 41044013 is about 6406.5601534677. The cubic root of 41044013 is about 344.9450672182.
Adding to 41044013 its reverse (31044014), we get a palindrome (72088027).
Subtracting from 41044013 its reverse (31044014), we obtain a palindrome (9999999).
It can be divided in two parts, 4104401 and 3, that multiplied together give a triangular number (12313203 = T4962).
The spelling of 41044013 in words is "forty-one million, forty-four thousand, thirteen".
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