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4011113 is a prime number
BaseRepresentation
bin1111010011010001101001
321112210012202
433103101221
52011323423
6221545545
746044131
oct17232151
97483182
104011113
11229a677
1214152b5
13aa5952
14765ac1
15543728
hex3d3469

4011113 has 2 divisors, whose sum is σ = 4011114. Its totient is φ = 4011112.

The previous prime is 4011103. The next prime is 4011127. The reversal of 4011113 is 3111104.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3988009 + 23104 = 1997^2 + 152^2 .

It is a cyclic number.

It is not a de Polignac number, because 4011113 - 28 = 4010857 is a prime.

It is a Sophie Germain prime.

It is an Ulam number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 4011094 and 4011103.

It is not a weakly prime, because it can be changed into another prime (4011103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2005556 + 2005557.

It is an arithmetic number, because the mean of its divisors is an integer number (2005557).

Almost surely, 24011113 is an apocalyptic number.

It is an amenable number.

4011113 is a deficient number, since it is larger than the sum of its proper divisors (1).

4011113 is an equidigital number, since it uses as much as digits as its factorization.

4011113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12, while the sum is 11.

The square root of 4011113 is about 2002.7763230076. The cubic root of 4011113 is about 158.8869758320.

Adding to 4011113 its reverse (3111104), we get a palindrome (7122217).

Subtracting from 4011113 its reverse (3111104), we obtain a palindrome (900009).

The spelling of 4011113 in words is "four million, eleven thousand, one hundred thirteen".