Base | Representation |
---|---|
bin | 1110111010001001… |
… | …1110011100100101 |
3 | 101022220111102112021 |
4 | 3232202132130211 |
5 | 31144003440023 |
6 | 1501041023141 |
7 | 201113365153 |
oct | 35642363445 |
9 | 11286442467 |
10 | 4002015013 |
11 | 1774040127 |
12 | 938324ab1 |
13 | 4ba178929 |
14 | 29d71a3d3 |
15 | 18652235d |
hex | ee89e725 |
4002015013 has 2 divisors, whose sum is σ = 4002015014. Its totient is φ = 4002015012.
The previous prime is 4002014971. The next prime is 4002015037. The reversal of 4002015013 is 3105102004.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3587770404 + 414244609 = 59898^2 + 20353^2 .
It is a cyclic number.
It is not a de Polignac number, because 4002015013 - 213 = 4002006821 is a prime.
It is a super-2 number, since 2×40020150132 = 32032248328554780338, which contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4002016013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2001007506 + 2001007507.
It is an arithmetic number, because the mean of its divisors is an integer number (2001007507).
Almost surely, 24002015013 is an apocalyptic number.
It is an amenable number.
4002015013 is a deficient number, since it is larger than the sum of its proper divisors (1).
4002015013 is an equidigital number, since it uses as much as digits as its factorization.
4002015013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 120, while the sum is 16.
The square root of 4002015013 is about 63261.4812741529. The cubic root of 4002015013 is about 1587.6675600348.
Adding to 4002015013 its reverse (3105102004), we get a palindrome (7107117017).
The spelling of 4002015013 in words is "four billion, two million, fifteen thousand, thirteen".
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