Base | Representation |
---|---|
bin | 11101101111011… |
… | …011000000010011 |
3 | 1021202220100001012 |
4 | 131233123000103 |
5 | 2010214030033 |
6 | 121302401135 |
7 | 15236115623 |
oct | 3557330023 |
9 | 1252810035 |
10 | 498970643 |
11 | 236724036 |
12 | 11b1301ab |
13 | 7c4b4702 |
14 | 4a3a8883 |
15 | 2dc13248 |
hex | 1dbdb013 |
498970643 has 2 divisors, whose sum is σ = 498970644. Its totient is φ = 498970642.
The previous prime is 498970613. The next prime is 498970651. The reversal of 498970643 is 346079894.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 498970643 - 210 = 498969619 is a prime.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 498970591 and 498970600.
It is not a weakly prime, because it can be changed into another prime (498970613) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 249485321 + 249485322.
It is an arithmetic number, because the mean of its divisors is an integer number (249485322).
Almost surely, 2498970643 is an apocalyptic number.
498970643 is a deficient number, since it is larger than the sum of its proper divisors (1).
498970643 is an equidigital number, since it uses as much as digits as its factorization.
498970643 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1306368, while the sum is 50.
The square root of 498970643 is about 22337.6507941189. The cubic root of 498970643 is about 793.1554843230.
The spelling of 498970643 in words is "four hundred ninety-eight million, nine hundred seventy thousand, six hundred forty-three".
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