Base | Representation |
---|---|
bin | 11101011101011… |
… | …011100000000001 |
3 | 1021110000201010201 |
4 | 131131123200001 |
5 | 2003012112311 |
6 | 121013325201 |
7 | 15151042666 |
oct | 3535334001 |
9 | 1243021121 |
10 | 494254081 |
11 | 233aa2452 |
12 | 119636801 |
13 | 7b522949 |
14 | 498dba6d |
15 | 2d5d09c1 |
hex | 1d75b801 |
494254081 has 2 divisors, whose sum is σ = 494254082. Its totient is φ = 494254080.
The previous prime is 494254031. The next prime is 494254093. The reversal of 494254081 is 180452494.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 344436481 + 149817600 = 18559^2 + 12240^2 .
It is a cyclic number.
It is not a de Polignac number, because 494254081 - 29 = 494253569 is a prime.
It is a super-2 number, since 2×4942540812 = 488574193170309122, which contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 494254081.
It is not a weakly prime, because it can be changed into another prime (494254031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 247127040 + 247127041.
It is an arithmetic number, because the mean of its divisors is an integer number (247127041).
Almost surely, 2494254081 is an apocalyptic number.
It is an amenable number.
494254081 is a deficient number, since it is larger than the sum of its proper divisors (1).
494254081 is an equidigital number, since it uses as much as digits as its factorization.
494254081 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 46080, while the sum is 37.
The square root of 494254081 is about 22231.8258584400. The cubic root of 494254081 is about 790.6484453274.
The spelling of 494254081 in words is "four hundred ninety-four million, two hundred fifty-four thousand, eighty-one".
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