Base | Representation |
---|---|
bin | 1001001100111011… |
… | …10010000100110011 |
3 | 110202022001200121112 |
4 | 10212131302010303 |
5 | 40104204340122 |
6 | 2134115543535 |
7 | 233265634421 |
oct | 44635620463 |
9 | 13668050545 |
10 | 4940308787 |
11 | 2105748127 |
12 | b5a5babab |
13 | 60968c34b |
14 | 34c1a4111 |
15 | 1ddab52e2 |
hex | 126772133 |
4940308787 has 2 divisors, whose sum is σ = 4940308788. Its totient is φ = 4940308786.
The previous prime is 4940308771. The next prime is 4940308837. The reversal of 4940308787 is 7878030494.
4940308787 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is an a-pointer prime, because the next prime (4940308837) can be obtained adding 4940308787 to its sum of digits (50).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4940308787 - 24 = 4940308771 is a prime.
It is a super-2 number, since 2×49403087872 = 48813301821818822738, which contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (4940308727) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2470154393 + 2470154394.
It is an arithmetic number, because the mean of its divisors is an integer number (2470154394).
Almost surely, 24940308787 is an apocalyptic number.
4940308787 is a deficient number, since it is larger than the sum of its proper divisors (1).
4940308787 is an equidigital number, since it uses as much as digits as its factorization.
4940308787 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1354752, while the sum is 50.
The square root of 4940308787 is about 70287.3302025337. The cubic root of 4940308787 is about 1703.1439843450.
The spelling of 4940308787 in words is "four billion, nine hundred forty million, three hundred eight thousand, seven hundred eighty-seven".
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