4938013441 has 3 divisors (see below), whose sum is σ = 4938083713. Its totient is φ = 4937943170.

The previous prime is 4938013427. The next prime is 4938013453. The reversal of 4938013441 is 1443108394.

The square root of 4938013441 is 70271.

It is a perfect power (a square), and thus also a powerful number.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a de Polignac number, because none of the positive numbers 2^k-4938013441 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 4938013441.

It is not an unprimeable number, because it can be changed into a prime (4938013411) by changing a digit.

It is a polite number, since it can be written in 2 ways as a sum of consecutive naturals, for example, 35136 + ... + 105406.

Almost surely, 2^4938013441 is an apocalyptic number.

4938013441 is the 70271-st square number.

4938013441 is the 35136-th centered octagonal number.

It is an amenable number.

4938013441 is a deficient number, since it is larger than the sum of its proper divisors (70272).

4938013441 is an frugal number, since it uses more digits than its factorization.

4938013441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 140542 (or 70271 counting only the distinct ones).

The product of its (nonzero) digits is 41472, while the sum is 37.

The cubic root of 4938013441 is about 1702.8801742272.

The spelling of 4938013441 in words is "four billion, nine hundred thirty-eight million, thirteen thousand, four hundred forty-one".