Base | Representation |
---|---|
bin | 1001001001110110… |
… | …00111011110100001 |
3 | 110200111101122001121 |
4 | 10210323013132201 |
5 | 40031044203233 |
6 | 2131353332241 |
7 | 232533041431 |
oct | 44473073641 |
9 | 13614348047 |
10 | 4914444193 |
11 | 20a209172a |
12 | b51a07081 |
13 | 604204759 |
14 | 3489902c1 |
15 | 1db6a692d |
hex | 124ec77a1 |
4914444193 has 4 divisors (see below), whose sum is σ = 4973654448. Its totient is φ = 4855233940.
The previous prime is 4914444187. The next prime is 4914444233. The reversal of 4914444193 is 3914444194.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 3914444194 = 2 ⋅1957222097.
It is a cyclic number.
It is not a de Polignac number, because 4914444193 - 213 = 4914436001 is a prime.
It is a super-2 number, since 2×49144441932 = 48303523452222842498, which contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (4914444593) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 29605003 + ... + 29605168.
It is an arithmetic number, because the mean of its divisors is an integer number (1243413612).
Almost surely, 24914444193 is an apocalyptic number.
It is an amenable number.
4914444193 is a deficient number, since it is larger than the sum of its proper divisors (59210255).
4914444193 is an equidigital number, since it uses as much as digits as its factorization.
4914444193 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 59210254.
The product of its digits is 248832, while the sum is 43.
The square root of 4914444193 is about 70103.0968859436. The cubic root of 4914444193 is about 1700.1665572681.
Subtracting from 4914444193 its reverse (3914444194), we obtain a palindrome (999999999).
The spelling of 4914444193 in words is "four billion, nine hundred fourteen million, four hundred forty-four thousand, one hundred ninety-three".
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