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49120193 is a prime number
BaseRepresentation
bin1011101101100…
…0001111000001
310102102120020102
42323120033001
5100033321233
64512452145
71134341363
oct273301701
9112376212
1049120193
11257aa801
121454a055
13a23ab05
146748d33
1544a41e8
hex2ed83c1

49120193 has 2 divisors, whose sum is σ = 49120194. Its totient is φ = 49120192.

The previous prime is 49120139. The next prime is 49120199. The reversal of 49120193 is 39102194.

It is a happy number.

49120193 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

Together with previous prime (49120139) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 47499664 + 1620529 = 6892^2 + 1273^2 .

It is a cyclic number.

It is not a de Polignac number, because 49120193 - 216 = 49054657 is a prime.

It is not a weakly prime, because it can be changed into another prime (49120199) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24560096 + 24560097.

It is an arithmetic number, because the mean of its divisors is an integer number (24560097).

Almost surely, 249120193 is an apocalyptic number.

It is an amenable number.

49120193 is a deficient number, since it is larger than the sum of its proper divisors (1).

49120193 is an equidigital number, since it uses as much as digits as its factorization.

49120193 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1944, while the sum is 29.

The square root of 49120193 is about 7008.5799560253. The cubic root of 49120193 is about 366.2295259709.

The spelling of 49120193 in words is "forty-nine million, one hundred twenty thousand, one hundred ninety-three".